1166 Summit (25 分)
Summit
题目描述:
A summit (峰会) is a meeting of heads of state or government. Arranging the rest areas for the summit is not a simple job. The ideal arrangement of one area is to invite those heads so that everyone is a direct friend of everyone.
Now given a set of tentative arrangements, your job is to tell the organizers whether or not each area is all set.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N (≤ 200), the number of heads in the summit, and M, the number of friendship relations. Then M lines follow, each gives a pair of indices of the heads who are friends to each other. The heads are indexed from 1 to N.
Then there is another positive integer K (≤ 100), and K lines of tentative arrangement of rest areas follow, each first gives a positive number L (≤ N), then followed by a sequence of L distinct indices of the heads. All the numbers in a line are separated by a space.
Output Specification:
For each of the K areas, print in a line your advice in the following format:
- if in this area everyone is a direct friend of everyone, and no friend is missing (that is, no one else is a direct friend of everyone in this area), print
Area X is OK.. - if in this area everyone is a direct friend of everyone, yet there are some other heads who may also be invited without breaking the ideal arrangement, print
Area X may invite more people, such as H.whereHis the smallest index of the head who may be invited. - if in this area the arrangement is not an ideal one, then print
Area X needs help.so the host can provide some special service to help the heads get to know each other.
Here X is the index of an area, starting from 1 to K.
Sample Input:
8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
2 4 6
3 3 2 1
Sample Output:
Area 1 is OK.
Area 2 is OK.
Area 3 is OK.
Area 4 is OK.
Area 5 may invite more people, such as 3.
Area 6 needs help.
思路:
想了半天还不知道要用什么算法,原来是个暴力模拟题。
代码:
#include "iostream"
#include "string.h"
using namespace std;
int rela[201][201];
int main(){
int m,n,k;
int head[201];
cin >>m>>n;
memset(rela,0,sizeof(rela));
for(int i=0;i<n;i++){
int a,b;
cin >>a>>b;
rela[a][b] = rela[b][a] = 1;
}
cin >>k;
int index = 0;
while(k--){
index++;
int p;
bool flag = false;
memset(head, 0 ,sizeof (head));
cin >>p;
int num[p+1];
for(int i=0;i<p;i++){
cin >>num[i];
head[num[i]] = 1;
}
// 开始暴力模拟
for(int i=0;i<p && !flag;i++){
for(int j=i+1;j<p;j++){
if(rela[num[i]][num[j]] != 1){
cout << "Area "<< index<<" needs help."<<endl;
flag = true;
break;
}
}
}
if (flag ) continue;
else{
// 开始判断是否有额外的数字可以加入
for(int i=1;i<=m;i++){
if(head[i] != 1){
for (int j=0; j<p;j++){
if(rela[num[j]][i] != 1){
flag = true;
break;
}
}
if(!flag){
cout <<"Area "<< index<<" may invite more people, such as "<<i<<"."<<endl;
flag = true;
break;
}else{
flag = false;
}
}
}
if(!flag){
cout << "Area "<< index<<" is OK."<<endl;
}
}
}
}
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