1984. Minimum Difference Between Highest and Lowest of K Scores
Minimum Difference Between Highest and Lowest of K Scores
题目描述:
You are given a 0-indexed integer array nums, where nums[i] represents the score of the ith student. You are also given an integer k.
Pick the scores of any k students from the array so that the difference between the highest and the lowest of the k scores is minimized.
Return the minimum possible difference.
Example 1:
Input: nums = [90], k = 1
Output: 0
Explanation: There is one way to pick score(s) of one student:
- [90]. The difference between the highest and lowest score is 90 - 90 = 0.
The minimum possible difference is 0.
Example 2:
Input: nums = [9,4,1,7], k = 2
Output: 2
Explanation: There are six ways to pick score(s) of two students:
- [9,4,1,7]. The difference between the highest and lowest score is 9 - 4 = 5.
- [9,4,1,7]. The difference between the highest and lowest score is 9 - 1 = 8.
- [9,4,1,7]. The difference between the highest and lowest score is 9 - 7 = 2.
- [9,4,1,7]. The difference between the highest and lowest score is 4 - 1 = 3.
- [9,4,1,7]. The difference between the highest and lowest score is 7 - 4 = 3.
- [9,4,1,7]. The difference between the highest and lowest score is 7 - 1 = 6.
The minimum possible difference is 2.
Constraints:
1 <= k <= nums.length <= 1000
0 <= nums[i] <= 105
思路:
排序一下就行
代码:
func minimumDifference(nums []int, k int) int {
n := len(nums)
if len(nums) == 1{
return 0
}
sort.Ints(nums)
minNum := 999999
for i:=0;i<n-k+1;i++{
minNum = min(minNum, nums[i+k-1]-nums[i])
}
return minNum
}
func min(a, b int)int{
if a>b{
return b
}else{
return a
}
}
代码效率:
执行用时:12 ms, 在所有 Go 提交中击败了94.74%的用户
内存消耗:5 MB, 在所有 Go 提交中击败了89.47%的用户
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